Alfred Eliab Buck Union United States Army officer
Alfred Eliab Buck is a 70 years old Union United States Army officer from Piscataquis County. Alfred Eliab Buck was born on February 07, 1832 (died on December 04, 1902, he was 70 years old) in Piscataquis County.
About
No, he died on 12/04/1902, 121 years ago. He was 70 years old when he died. He died in Tokyo and buried in Arlington National Cemetery .
Education
He graduated from Colby College
What was Alfred's zodiac sign?Alfred Eliab Buck zodiac sign was aquarius.
Other facts about Alfred Eliab Buck
| Place of death | Tokyo |
|---|---|
| Work location | Washington, D.C. |
| Country of citizenship | United States Of America |
| Date of death | 1902-12-04T00:00:00Z |
| Name in native language | Alfred Eliab Buck |
| Member of political party | Republican Party |
| Given name | Alfred |
| Position held | United States Representative |
| Family name | Buck. Show people with the surname Buck |
| Place of birth | Piscataquis County |
| Place of burial | Arlington National Cemetery |
| Languages spoken, written or signed | English |
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